Find the value of ab+bc+ca, if a+b+c=9 and a2+b2+c2=35
Answers
(a+b+c)2=a2+b2+c2+2ab+2bc+2ca,weget the answer (9)2=35+2(ab+BC+CA
2(ab+BC+CA)=(9)2-35
2(ab+BC+CA) =81-35then we get ab+BC+CA=46/2 so ab+BC+CA=23
The value of ab + bc + ca = 23
Given :
a + b + c = 9 and a² + b² + c² = 35
To find :
The value of ab + bc + ca
Formula :
(a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca
Solution :
Step 1 of 2 :
Write down the given data
Here it is given that
a + b + c = 9 and a² + b² + c² = 35
Step 2 of 2 :
Find the value of ab + bc + ca
(a + b + c)² = a² + b² + c² + 2ab + 2bc + 2ca
⇒ (a + b + c)² = a² + b² + c² + 2(ab + bc + ca)
⇒ 2(ab + bc + ca) = (a + b + c)² - ( a² + b² + c² )
⇒ 2(ab + bc + ca) = (9)² - 35
⇒ 2(ab + bc + ca) = 81 - 35
⇒ 2(ab + bc + ca) = 46
⇒ ab + bc + ca = 46/2
⇒ ab + bc + ca = 23
Hence the value of ab + bc + ca = 23
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