Math, asked by mofahd7000, 1 year ago

Find the value of (abc)^2 when a=1,b=2,c=3.

Answers

Answered by tahseen619
5

a = 1 \:  \:  \:  \: b = 2 \:  \:  \: c = 3 \\  {(abc)}^{2}  \\  {(1 \times 2 \times 3)}^{2}  \\  {6}^{2}  = 36

Noeltony: Thank you
Answered by psingh76
5

Answer:

36

Step-by-step explanation:

As a = 1, b = 2 and c = 3

So,

(\text {abc})^2=(1 \times 2 \times 3)^2=6^2 = 36

Similar questions