Find the value of ABC
AB
×BA
-------
BCB
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Answer: B^3+B
Step-by-step explanation: (10A+B)(10B+A)=100B+10C+B
100AB+10A^2+10B^2+AB=100B+10C+B
101AB+10(A^2+B^2)=101B+10C =>
=> AB=B ; A^2+B^2=C => A=1 ; C=B^2+1
ABC=B(B^2+1)=B^3+B
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