Question

Find the value of acceleration due to gravity at a hieght of 400Km above the surface of earth. Radius of earth =6400Km.

Answer 1

effect of height
g'= (1- 2h÷R)g
put r is 6400 km h is 400 km
g = 1.23

Answer 2

Answer:

$g=8.624*10^6 \frac{m}{s^2}$

Explanation:

Let us use the formula of gravity in a particular hieght

$g=\frac{Gm}{(r+h)^{2} }$

We are given that

$G=6.674*10^{-11 }m^3 kg^{-1} s^{-2}$

$h=400km\\r=6400km$

Let us now substitute the values.

$g=\frac{6.674*10^{-11 }*5.98*10^{24}}{(6400+400)^{2} }$

$g=\frac{39.88*10^{13 }}{(6800)^{2} }$

 $=\frac{39.88*10^{13}*10^{-7}}{4.624}$

 $=8.624*10^6 \frac{m}{s^2}$