Question

Find the value of acceleration due to gravity at the surface of moon whose mass is 7.4

Answer 1

Answer:

Acceleration due to Gravity =g

= G M/R^2

= (6.67×10^-11×7.4×10^22)/ 1.75×10^6×1.75×10^6

= (6.67 × 7.4/1.75×1.75) × 10^-1

= 49.358/30.625

= 1.61 Newton

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Answer 2

Answer:

Here is the solution

$g = \frac{GM}{ {r}^{2} }$

M = MASS OF MOON = 7.4 × 10 -¹¹

r = Radius of Moon = 1.773 × 100³

$g = \frac{6.67 \times {10}^{ - 11} \times 7.4 \times {10}^{22} }{ ({1.73 \times {10}^{6} })^{2} } \\ g = \frac{6.67 \times 7.4 }{{1.73}^{2} \times 10 } \\ g = \frac{49.358}{29.92} \\ g = 1.64 \: m/ {s}^{2}$

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