Question

find the value of AD in terms of x

Answer 1

from given info,

Let AD=a

from pythagorous theorem,

x∧2=a∧2+(x/2)∧2

x∧2-(x/2)∧2=a∧2

(4x∧2-x∧2)/4=a∧2

3x∧2/4=a∧2

a=√3x/2