find the value of alfa³+beta³
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Step-by-step explanation:
The basic formula is
(a+b)3=a^3 +b^3+3^ab(a+b)
Rearranging the terms to obtain the desired result we get;
a^3+b^3=(a+b)3–3^ab(a+b)
Simplifying it further by taking (a+b) common we obtain,
a^3+b^3
=[a+b] [(a+b)2–3^ab(a+b)]
=[a+b] [a^2+b^2+2ab-3ab] (expanding (a+b)2)
=[a+b] [a^2-ab+b^2]
THIS IS THE BEST EXPRESSION FOR THIS QUESTION(THOUGH IT SEEMS LENGTHY)
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