Question

Find the value of alpha+beta from quadratic equations 8x^2+2x-3=0

Answer 1

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The two roots of the equation 8x^2-3x+27=0is α &β

α+β=-b/a=-(-3)/8

αβ=c/a=27/8

Now (α^2/β)^1/3 + (β^2/α)^1/3

=α^2/3/β^1/3 + β^2/3/α^1/3

=α^2/3*α^1/3 +β^2/3*β^1/3/(αβ)^1/3

=α+β/(αβ)^1/3

=3/8/(27/8)^1/3

=3/8/3√27/3√8

=3/8/3/2

=1/4

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