Question

find the value of b if x^4-2x^3+3x^2-bx+5 is exactly divisible by (x-3)​

Answer 1

Step-by-step explanation:

x-3 is exactly divisible it means that the value of x is 3

x=3

substitute 3 everywhere instead of x

3⁴-2(3)³+3(3)²-3b+5

=243-54-3b+5

=194-3b

As it was mentioned that x=3 is exactly divisible so,

194-3b=0

-3b=-194

b=64.67