find the value of b if x^4-2x^3+3x^2-bx+5 is exactly divisible by (x-3)
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Step-by-step explanation:
x-3 is exactly divisible it means that the value of x is 3
x=3
substitute 3 everywhere instead of x
3⁴-2(3)³+3(3)²-3b+5
=243-54-3b+5
=194-3b
As it was mentioned that x=3 is exactly divisible so,
194-3b=0
-3b=-194
b=64.67
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