find the value of b1/b2 for 2×+3y=8 and 4×+5y=8
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Step-by-step explanation:
Given 2x+3y+8 = 0 ...(1)
4x+5y+14 = 0 ...(2)
multiply equation. (1) by 5 and equation (2) by 3 we get
10x + 15y + 40 = 0
12x + 15y + 42 = 0
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___________________
-2x-2=0
[x = -1] from equation.(1) 3y = 8 -2x
y=310
Hence using cross multiplication method intersection point of line 1 & 2 are(−1,310)
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