find the value of c and its factrisations
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Heyy here is U r Ans =>>>
Simplifying 3c2 + -17c + 14 = 0 Reorder the terms:
14 + -17c + 3c2 = 0 Solving 14 + -17c + 3c2 = 0 Solving for variable 'c'. Factor a trinomial.
(1 + -1c)(14 + -3c) = 0
Subproblem 1
Set the factor '(1 + -1c)' equal to zero and attempt to solve:
Simplifying 1 + -1c = 0 Solving 1 + -1c = 0 Move all terms containing c to the left, all other terms to the right.
Add '-1' to each side of the equation.
1 + -1 + -1c = 0 + -1 Combine like terms:
1 + -1 = 0 0 + -1c = 0 + -1 -1c = 0 + -1 Combine like terms:
0 + -1 = -1 -1c = -1 Divide each side by '-1'. c = 1 Simplifying c = 1
I hope this helps U :-)
Simplifying 3c2 + -17c + 14 = 0 Reorder the terms:
14 + -17c + 3c2 = 0 Solving 14 + -17c + 3c2 = 0 Solving for variable 'c'. Factor a trinomial.
(1 + -1c)(14 + -3c) = 0
Subproblem 1
Set the factor '(1 + -1c)' equal to zero and attempt to solve:
Simplifying 1 + -1c = 0 Solving 1 + -1c = 0 Move all terms containing c to the left, all other terms to the right.
Add '-1' to each side of the equation.
1 + -1 + -1c = 0 + -1 Combine like terms:
1 + -1 = 0 0 + -1c = 0 + -1 -1c = 0 + -1 Combine like terms:
0 + -1 = -1 -1c = -1 Divide each side by '-1'. c = 1 Simplifying c = 1
I hope this helps U :-)
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hope it help you
mark as brainiest dear
mark as brainiest dear
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