Question

Find the value of c for infiniyely many solutions​

Answer 1

Answer:

please post the equations first then only we can find the value of c

For help

a1/a2= b1/b2=c1/c2

(for infinitely many solutions)

Answer 2

Step-by-step explanation:

For no value of c the pair of equations will have infinitely many solutions.

Step-by-step explanation:

Given : The pair of equation cx-y=2cx−y=2 and 6x-2y=36x−2y=3 will have infinitely many solution.

To find : The value of 'c'?

Solution :

Condition for infinitely many solutions is

\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}

a

2

a

1

=

b

2

b

1

=

c

2

c

1

Given lines are cx-y=2cx−y=2 and 6x-2y=36x−2y=3

So, a_1=c,b_1=-1,c_1=-2,a_2=6,b_2=-2,c_2=-3a

1

=c,b

1

=−1,c

1

=−2,a

2

=6,b

2

=−2,c

2

=−3

Substitute in the condition,

\frac{c}{6}=\frac{-1}{-2}=\frac{-2}{-3}

6

c

=

−2

−1

=

−3

−2

\frac{c}{6}=\frac{1}{2}=\frac{2}{3}

6

c

=

2

1

=

3

2

Take first two,

\frac{c}{6}=\frac{1}{2}

6

c

=

2

1

Solve,

c=3c=3

Take first and last,

\frac{c}{6}=\frac{2}{3}

6

c

=

3

2

Solve,

c=4c=4

Since, c has different values.

Hence, For no value of c the pair of equations will have infinitely many solutions.

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