Question

Find the value of cos⁻¹ (cos $\frac{17\pi}{6}$).

Answer 1

Answer:

The answer to this question is simply  " 17π/6 ".

Explanation:

This question is a very simple question.

cos is a Trigonometric function.

And cos⁻¹ is an Inverse Trigonometric Function. It is the inverse of the cos function.

Now we have given that  

cos⁻¹(cos 17π/6)

So both the functions will cancel each other and we get the answer which is

 " 17π/6 "

I Hope that it will help you.

Answer 2

Answer:

cos⁻¹ (cos 17π/6)=5π/6

Step-by-step explanation:

To find the value of

$cos^{-1}(cos\:\frac{17\pi }{6})$

since cos⁻¹ cancels cos only if 17π/6 lies between principal value branch[0,π]

cos(17π/6)=cos(2π+5π/6)

=> cos(5π/6)         ∵period of cos is 2π

=> cos⁻¹[cos(5π/6)]   here 5π/6 belongs to [0,π]

so

=> 5π/6

cos⁻¹ (cos 17π/6)=5π/6

hope it helps you.