find the value of cos^2 13cos^2 47 +cos^2 73
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Answer:
L.H.S. =
2
1
[1 + cos 146
∘
+ 1 + 1 + cos 94
∘
+ cos 120
∘
+ cos 26
∘
]
=
2
1
[2−
2
1
+cos146
∘
+cos94
∘
+cos26
∘
]
4∵cos120
∘
=−
2
1
=
2
1
[
2
3
+cos146
∘
+2cos60
∘
cos34
∘
]
=
2
1
[
2
3
−cos34
∘
+cos34
∘
]=
4
3
.
Step-by-step explanation:
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