find the value of cos75 ×cos15_sin75×sin15
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Answer:
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Method 1
Use:
cos(α−β)=cos(α)cos(β)−sin(α)sin(β)
So:
cos75∘cos15∘+sin75∘sin15∘=cos(75∘−15∘)=cos60∘=12
Method 2
Use:
cos(θ)=sin(90∘−θ)
sin(θ)=cos(90∘−θ)
sin(2θ)=2sinθcosθ
So:
cos75∘cos15∘+sin75∘sin15∘=sin15∘cos15∘+sin15∘cos15∘=sin30∘=12
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