Find the value of cot 1° cot 2° cot 3°........ cot 89°.
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cot1.cot2.cot3 ……………..cot87.cot88.cot89
we know,
cot1 =cot(90-89) = tan89
cot1.cot89 =1
Similarly,
cot2.cot88 =1
cot3.cot87 =1
{cot1.cot89}{cot2.cot88}{cot3.cot87}...
=1 × 1 × 1 × 1 …
=1
Hope it helps you...
Please mark my answer as the brainliest answer...
we know,
cot1 =cot(90-89) = tan89
cot1.cot89 =1
Similarly,
cot2.cot88 =1
cot3.cot87 =1
{cot1.cot89}{cot2.cot88}{cot3.cot87}...
=1 × 1 × 1 × 1 …
=1
Hope it helps you...
Please mark my answer as the brainliest answer...
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