Find the value of cot40°/tan50°-cos35°/2sin55°
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haha after thinking a lil I finally got it!
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cot40/tan50-cos35/2sin55
=tan(90-40)/tan50-sin(90-35)/2sin55
=tan50/tan50-sin55/2sin55
=1-1/2
=1/2 (ans)
=tan(90-40)/tan50-sin(90-35)/2sin55
=tan50/tan50-sin55/2sin55
=1-1/2
=1/2 (ans)
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