Question

Find the value of critical angle of water if the ray of light enters from water into air .The refractive index of water is 1.33.( Sin-1(0.752) = 48.8 degree )
give a full solution please

Answer 1

Answer:

Explanation:

Refractive index of water nw =1.33  

The refractive index of air na=1

Let C is the critical angle of water .

The Snell's law is  

SinC/Sin 90 = na/nw

Sin C = 1/1.33

Sin C =0.752

C=sin^-1 (0.752)

C= 48.76