Question

find the value of deterimants​

Answer 1

Answer:

$3 \sqrt{6} \times 2 - - 4 \sqrt{2 } \times 5 \sqrt{ 3}$

$6 \sqrt{6 } - - 20 \sqrt{6}$

$6 \sqrt{6 } + 20 \sqrt{6}$

$26 \sqrt{6}$