Question

Find the value of determinant :
Log x Log y Log z
Log 2x Log 2y Log 2z
Log 3x. Log 3y Log 3z

Answer 1

Find the value of determinant :
Log x Log y Log z
Log 2x Log 2y Log 2z
Log 3x. Log 3y Log 3z
Let x denote the required logarithm. 

Therefore, log2√3 1728 = x 

or, (2√3)x = 1728 = 26 ∙ 33 = 26 ∙ (√3)6 

or, (2√3)x = (2√3)6 

Therefore, x = 6. 


(ii) 0.000001 to the base 0.01. 

Answer 2

Answer:

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