Question

Find the value of determinants
48 6 18
24 0 6
36. 0. 18

Answer 1

Answer:

$6480$

Step-by-step explanation:

we have been given that

$A=\left[\begin{array}{ccc}48&6&3\18\\24&0&6\\36&0&18\end{array}\right]$

find the value determinant:

$\left[\begin{array}{ccc}A\\\end{array}\right] =\left[\begin{array}{ccc}1\48&6&18\\24&0&6\\36&0&18\end{array}\right] \\=48\left[\begin{array}{ccc}0&6\\0&18\\\end{array}\right] -6\left[\begin{array}{ccc}24&6\\36&18\\\end{array}\right]+18\left[\begin{array}{ccc}24&0\\36&18\\\end{array}\right]$

$=48(0-0)-6(432-216)+18(432-0)\\=0-6(216)+18(432)\\=-1296+7776\\=6480$

Hence,the value of determinants is 6480.