Find the value of discriminant of quadratic equation x²+7x-1=0
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Answered by
29
In a quadratic equation of the form-
ax²+bx+c=0
The discriminant(d)=b²-4ac
Here,
x²+7x-1=0
Therefore D=7²-4(1)(-1)=49+4=53
ax²+bx+c=0
The discriminant(d)=b²-4ac
Here,
x²+7x-1=0
Therefore D=7²-4(1)(-1)=49+4=53
Haremking:
It's 49+4 not '49-4'
sorry i have edited
Answered by
4
Answer:
Step-by-step explanation:
Discriminant=(7)^2-4(1*-1)=53
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