find the value of discriminant of the quadratic equation 2x³+5x-4=0.
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Answered by
2
Answer:
b²-4ac
compare given equation with ax²+bx+c=0
a=2,b=5,c=-4
(5)²-4(2)(-4)
25+32
57 .............. the given equation has two real distinct roots
Step-by-step explanation:
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Answered by
2
Step-by-step explanation:
D= √(b2-4ac)
in the given equation
a=2 b=5 c=-4
√(25-4×2×-4)
√(57)
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