Question

find the value of discriminant of x^2-2x-3=0​

Answer 1

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We know that,

discriminant (d) =b²-4ac

so,

here , in the equation,

a =1

b=-2

c = -3

so ,

d =b² -4ac

$d = {( - 2)}^{2} - 4 \times 1 \times ( - 3) \\ 4 - 4 \times ( - 3) \\ 4 - ( - 12) \\ 4 + 12 \\ d = > 16$

So, the value of

discriminant is 16.

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