Question

Find the value of DX and D for the equation.
2x+3y=4;7x-5y=2

Answer 1

$x =\dfrac{26}{31}$ and $y=\dfrac{72}{93}=\dfrac{24}{31}$

Step-by-step explanation:

The given equationds are:

2x + 3y = 4       ......(1)

and 7x - 5y = 2       ......(2)

To find, the value of x and y =

Multiplying (1) by 5 and (2) by 3, we get

10x + 15y = 20            ......(3)

and 21x - 15y = 6        ......(4)

Adding (3) and (4), we get

10x + 21x = 20 + 6

⇒ 31x = 26

⇒ x = $\dfrac{26}{31}$

Put  x = $\dfrac{26}{31}$ in (1), we get

$2(\dfrac{26}{31})+3y=4$

⇒$3y=4-\dfrac{52}{31} =\dfrac{124-52}{31} =\dfrac{72}{31}$

⇒$y=\dfrac{72}{93}=\dfrac{24}{31}$

Hence, $x =\dfrac{26}{31}$ and $y=\dfrac{72}{93}=\dfrac{24}{31}$