Find the value of e³ using first 5 terms of the expansion of eˣ.
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we know by the concept of expansion,
expansion of = 1 + x + x²/2! + x³/3! + x⁴/4! + ......
we have to find value of e³ using first 5 terms.
e.g., e³ = 1 + 3 + 3²/2! + 3³/3! + 3⁴/4!
= 1 + 3 + 9/2 + 27/6 + 81/24
= 131/8
= 16.375
hence, value of e³ = 16.375
expansion of = 1 + x + x²/2! + x³/3! + x⁴/4! + ......
we have to find value of e³ using first 5 terms.
e.g., e³ = 1 + 3 + 3²/2! + 3³/3! + 3⁴/4!
= 1 + 3 + 9/2 + 27/6 + 81/24
= 131/8
= 16.375
hence, value of e³ = 16.375
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