Question

In a G.P. if third term is 63 and the sixth term is 1701, find its nth term.

Answer 1

Answer:

Step-by-step explanation:

A3=63

A+2d=63---1

A7=1701

A+6d=1701---2

Subtracting 2 from 1

4d=1638

D=412 now find A and out the values in the following eq

Nth term =a+(n-1)d

Answer 2

Answer:

nth term =  7 *3ⁿ⁻¹

Step-by-step explanation:

GP is geometric Progression

where

nth term of an GP = ar^(n-1)

a = first term of Geometric Progression

r = common ratio of Geometric progression

third term of GP will be

3rd term = ar³⁻¹ = ar² = 63

6th term = ar⁶⁻¹ = ar⁵ = 1701

dividing 6th term by 3rd term

ar⁵/ar² = 1701/63

r³ = 27

r³ = 3³

taking cube root both sides

r = 3

a(3)² = 63

9a = 63

a = 7

nth term = 7 *3ⁿ⁻¹