In a G.P. if third term is 63 and the sixth term is 1701, find its nth term.
Answers
Answered by
3
Answer:
Step-by-step explanation:
A3=63
A+2d=63---1
A7=1701
A+6d=1701---2
Subtracting 2 from 1
4d=1638
D=412 now find A and out the values in the following eq
Nth term =a+(n-1)d
Answered by
14
Answer:
nth term = 7 *3ⁿ⁻¹
Step-by-step explanation:
GP is geometric Progression
where
nth term of an GP = ar^(n-1)
a = first term of Geometric Progression
r = common ratio of Geometric progression
third term of GP will be
3rd term = ar³⁻¹ = ar² = 63
6th term = ar⁶⁻¹ = ar⁵ = 1701
dividing 6th term by 3rd term
ar⁵/ar² = 1701/63
r³ = 27
r³ = 3³
taking cube root both sides
r = 3
a(3)² = 63
9a = 63
a = 7
nth term = 7 *3ⁿ⁻¹
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