Question

find the value of each if the following algebraic expressions: 20y - 32 + 18x for y=3 & x= -2
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Answer 1

Step-by-step explanation:

let p(x) = 20y-32+18x

=20y+18x-32

put, y=3 and x=(-2) in p(x)

then,

=20(3)+18(-2)-32

=60+(-36)-32

=60-36-32

= -8

hence, the value of p(x) is (-8).

Answer 2

Answer:

Value of given expression, $20y -32 + 18x$  is $-8$ .

Step-by-step explanation:

To find : value of given expression, $20y -32 + 18x$

Given : $y = 3 , x = -2$

Solution :

• According to question we have find the value of given expression   $20y -32 + 18x$ by substituting the given value of $x$  and $y$ .
• After substituting the values by performing arithmetic operations we find the value of given expression    .

         $20y -32 + 18x \\\\= 20 ( 3 ) -32 + 18 ( -2) \\\\ =60 -32 -36\\\\= 28-36 \\\\ =-8$