Question

find the value of each of the following (3^0-4^0)×7^0

Answer 1

as a^0=1
(3^0-4^0)×7^0
(1-1)×1
(0)×1
=0
so 0 is the answer
Hope it is helpful to u

Answer 2

heya....
Ur solution..
(3^0-4^0)×7^0
(1-1)1
0×1
1.... answer.
:)