Question

find the value of each of the following polynomials at the points x=, -3 and 1/2 (iii) 5-6x+x²​

Answer 1

Step-by-step explanation:

${x}^{2} - 6x + 5 \\ = {x}^{2} - 5x - x + 5 \\ = x(x - 5) - 1(x - 5) \\ = (x - 1)(x - 5) \\ x = 1 \: and \: 5$

$at \: x = - 3 \\ {x }^{2} - 6x + 5 \\ = ( { - 3})^{2} - 6( - 3) + 5 \\ = 9 + 9 + 5 \\ = 23$

$and \: at \: x = \frac{1}{2} \\ (\frac{1}{2} ) ^{2} - 6( \frac{1}{2} ) + 5 \\ = \frac{1}{4} - \frac{6}{2} + 5 \\ = \frac{1}{4} - 3 + 5 \\ = \frac{1}{4} + 2 \\ = \frac{1 + 8}{4} \\ = \frac{9}{8}$