CBSE BOARD XII, asked by harshitha72, 11 months ago

find the value of expression (18x^+16y^-72xy)when x=2/3and y=3/4 ​

Answers

Answered by KrishSuthar
3

Answer:

72

Explanation:

=16×2+18×3-72×2×3

=36+48-72×6

=84-72×6

=12×6

Ans=72

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