Math, asked by yeduvakayugandh3042, 1 year ago

Find the value of expression 81x^2+16y^2-72xy, if x=2 and y=3/4

Answers

Answered by harjotsinghbhinder13
0
I think put values of x=2 and y=3/4 in equation then you will get answer
try it yourself
it will make your ability strong
hope it helps!
Answered by MonarkSingh
0
\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hello Friend}}}

Here is your answer

If x = 2
y = 3/4

81x {}^{2}  + 16y {}^{2}  - 72xy \\  = 81(2) {}^{2}  + 16( \frac{3}{4} ) {}^{2}  - 72 \times 2 \times  \frac{3}{4}  \\  = 81 \times 4 + 3 \times 3  - 36 \times 3 \\  = 324 + 9 - 108 \\  = 225
Hope it helps you
Similar questions