find the value of expression ?
sin²35°+sin²55° sec²23°- cot²67°
---------------------- + ------------------------ + sin²63° + cos63°.sin27°
cos²40°+cos²50° sec²36°- cot²54°
Answers
Answered by
0
Answer:
1
Step-by-step explanation:
∴sin²35°+cos²(90-55) sec²23°-tan²(90- 67 ) __________+___________+sin²63°+cos63°cos(90-27)°cos²40°+sin²(90-50)sec²36°-tan²(90-54)
∴sin²35+cos²35 sec²23-tan²23² _________ +________ +sin²63+ cos63 ×cos63 cos²40+cos²40 sec²36-tan²36
∴1×1×1×1×1 [sin²+cos²=1 and sec²-tan²=1]
=1
Similar questions