Question

find the value of expression :- (x²-y²)(x²+y²)+(y²-z²)(y²+z²)+(z²-x²)(z²+x²) when x = 12 and y= 13​

Answer 1

Answer:

0

Step-by-step explanation:

$( {x}^{2} - {y}^{2} )( {x}^{2} + {y}^{2} ) + ( {y}^{2} - {z}^{2} )( {y}^{2} + {z}^{2} ) + ( {z}^{2} - {x}^{2} )( {z}^{2} + {x}^{2} ) \\ = {x}^{4} - {y}^{4 } + {y}^{4} - {z}^{4} + {z}^{4} - {x}^{4} \\ = 0$

Answer 2

Answer:

this is correct......................