Question

. Find the value of following expressions.
(i) (a-b)²+4ab, ifa=
1\4,b =-3
(iii) (x + y)² – (x² + y² + 2xy), if x=2, y=-2​

Answer 1

Answer:

i)121/16

ii)0

Step-by-step explanation:

$((1 \div 4) - ( - 3)) {}^{2} + 4(1 \div 4)( - 3) = (13 \div 4) {}^{2} - 3 = (169 - 48) \div 16 = 121 \div 16$

$(2 - 2) {}^{2} - (4 + 4 - 8) = 0$