Question

Find the value of ∆ for weakly guiding fiber with n1 = 1.5 and n2 = 1.477.

Answer 1

Answer:

The value of ∆ for weakly guiding optical fiber is 0.0153

Explanation:

As we know that for weakly guiding optical fiber the value of ∆ is defined as

$∆ = \frac{n_1 - n_2}{n_1}$

here we know that

$n_1 = 1.5$

$n_2 = 1.477$

so we will have

$∆ = \frac{1.5 - 1.477}{1.5}$

$∆ = 0.0153$

#Learn

Topic : Optical Fiber

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