Question

FIND THE VALUE OF 'g':​

Answer 1

Answer:

g=GMR^-2

On differentiating,

dg/dr= -2× g/R

-Sign accounts for the decrease in the radius.

Now substituting dr as -1, we get dg = 2times a quantity. Thus g increases by 2%

Answer 2

$\frac{R_1-R}{R}×100=-1\\\\R_1=0.99R\\\\g_1=\frac{GM}{{0.99R}^{2}}=\frac{g}{{0.99}^{2}}\because\:g=\frac{GM}{{r}^{2}}\\\\\%\:change\:in\:g=\frac{g_1-g}{g}×100\\\\=\huge(\small\frac{1}{{0.99}^{2}-1}\huge)\small ×100=\underline{2 \%}$