Question

find the value of give equation​

Answer 1

Sin 15°= Sin(45–30)°

W.k.t, Sin(A-B) = SinACosB - CosASinB

Therefore, Sin(45–30)°= Sin45°Cos30° - Cos45°Sin30°

W.k.t, sin45°= cos45°=1/√2, sin30°= 1/2, cos30°=√3/2

Therefore, Sin(45–30)°= (1/√2)(√3/2)-(1/√2)(1/2)

= (√3/2√2)-(1/2√2)

= (√3–1)/2√2