find the value of given figure
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(3x-10)+(2x-20)=180[ straight line]
3x-10+2x-20=180
5x-30=180
5x=180+30
5x=210
X=210/5
X=42°
First angle =3×42-10=116
Second angle=2×42-20=64
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3x-10+2x-20=180
5x-30=180
5x=180+30
5x=210
X=210/5
X=42°
First angle =3×42-10=116
Second angle=2×42-20=64
Mark it as brainliast pls
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hope it is helpful..
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