Question

find the value of given question​

Answer 1

Answer:

Step-by-step explanation:

$(x - \frac{1}{x})^{2} = x^{2} + \frac{1}{x^{2}}  - 2$

1 = $x^{2} + \frac{1}{x^{2}} - 2$

-1 = $x^{2} + \frac{1}{x^{2}}$

$(x + \frac{1}{x})^{2} = x^{2} + \frac{1}{x^{2}}  + 2$

$(x + \frac{1}{x})^{2} = -1 + 2 = 1$

$x + \frac{1}{x} = ± 1$

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