Question

Find the value of h[f(1,2,3), g(2,1,-2), h(1,-1,-1)].

a. 0.5

b. none

c. 1

d. 0

Answer 1

Given :   f (a , b, c) = a³ - b² + c   , g(a , b , c) = (a + b + c)/2  , h(a , b , c) = abc

[f(1,2,3), g(2,1,-2), h(1,-1,-1)].

To Find : Value of h

Solution:

f (a , b, c) = a³ - b² + c

g((a , b , c) = (a + b + c)/2

h(a , b , c) = abc

h(1,-1,-1)

a = 1

b = - 1

c = -1

h(a , b , c) = abc

=>  h(1,-1,-1)  = 1(-1)(-1)

=>  h(1,-1,-1)  = 1

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Answer 2

Answer:d

Step-by-step explanation:

1+2+3 = 6

2+1-2 = -1

1-1-1 = -2

= 6-1-2÷3

=0