Math, asked by Diksha12341, 9 months ago

• Find the value of :
i) √(144)^-2
ii) (3)^-2


• Evaluate :
(3^2+4^2)^1/2​

Answers

Answered by sammane2514
1

Answer:

i). 6.9444 \times {10}^{ - 3}

ii). 5

Step-by-step explanation:

i)

 \sqrt{(144) {( - 2)}^{2} }  =  {144}^{( - 2) \times ( \frac{1}{2} }  \\  {144}^{( - 1)}   \\  \frac{1}{144} \\ 6.9444 \times  {10}^{ - 3}

ii)

 {({3}^{2}  +  {4}^{2})}^{ \frac{1}{2} }  \\  {(9 + 16)}^{ \frac{1}{2} }  \\  {25}^{ \frac{1}{2} }  \\  \sqrt{25}  \\ 5

Answered by bhanuprakashreddy23
1

Step-by-step explanation:

(√144)^-2=1/(√144)^2=1/144

(3)^-2=1/3^2=1/9

((3^2+4^2)&1/2=√(9+16)=√25=5

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