Question

Find the value of (i)sin 150° (ii)cos 135° (iii)tan 120°


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Answer 1

Answer:

1 upon 2

-2/3

3

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Answer 2

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$(i) \: sin150° = \sin(90° + 60°) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: = \cos(60°) \\ \: = \frac{1}{2}$

$(or)$

$= \sin(150°) = \sin(180° - 30°) \\ = \sin(30°) \\= \frac{1}{2}$

$(ii) \cos(135°) = \cos(90° + 45°) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = - \sin(45°) \\ = - \frac{1}{ \sqrt{2} }$

$(or)$

$\cos(135°) = \cos(180° - 45°) \\ \: \: \: \: \: \: \: \: \: = - \cos(45°) \\ = - \frac{1}{ \sqrt{2} }$

$(iii) \tan(120°) = \tan(180° - 60°) \\ = - \tan(60°) \\ = - \sqrt{3}$

$(or)$

$write \: \tan(120°) \: as \: \tan(90° + 30°) \: and \: find \: the \: value.$