Question

find the value of
(i) x
3
– y
3
– 12xy – 64, when x – y – 4 = 0.​

Answer 1

Step-by-step explanation:

a³=x³ i.e. a= x

b³=y³ i.e. b= y

64=c³ i.e. c= 4

We know that, when a+b+c = 0, then a³+b³+c³ = 3abc

Therefore,

x³+y³+64 = 3*4(xy)

= 12xy

Answer 2

Answer:

x³-y³-12xy-64=(x-y-4)(x²+y²+16-2xy-8y-8x)

x³-y³-12xy-64=(0)(x²+y²+16-2xy-8y-8x)

x³-y³-12xy-64=0