Question

Find the value of i81 i19 i16 i102

Answer 1

Answer:

${i}^{81} = i \\ {i}^{19} = - 1 \\ {i}^{16} = 1 \\ {i}^{102} - 1$

Step-by-step explanation:

${i}^{81} = {(i)}^{4\times 20} \times i = i$

${i}^{19} = {i}^{4 \times 4} \times {i}^{2} \\ = {i}^{2} \\ = - 1$

${i}^{16} = {i}^{4 \times 4} = 1$

${i}^{102} = {i}^{4 \times 25} \times {i}^{2} \\ = {i}^{2} \\ = - 1$