Question

Find the value of ′′ if 3^2−8 /225 = 5^3/5^

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Answer 1

Answer:

{ 3^(2x-8)}/225 = 5^3/5^x.

or {3^(2x-8)}/(3^2×5^2)=(5)^(3-x).

or {3^(2x-10)} = (5)^(5-x).

or (3^2)^(x-5) = (5)^(5-x).

or 9^(x-5) = 1/(5)^(x-5).

or (45)^(x-5) = 1.

or (45)^(x-5) = (45)^ 0.

Therefore x-5 =0.