Parabola y=(p-3) x^2+4px+1 memiliki sumbu simetri x=1. Tentukan nilai p!
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n! = 1 × 2 × 3 × …× (n – 2) × (n – 1) × n atau
n! = n × (n – 1) × (n – 2) × … × 3 × 2 × 1
1! = 1 dan 0! = 1
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