Question

find the value of k,

Answer 1

x-1=0
x=1
substitute value of x in p(x)
4(1)^3+3(1)^2-4(1)+k=0
4+3-4+k=0
3+k=0
k=-3....
value of k is -3..

Answer 2

Hey friend!!

Here's ur answer..



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If x-1 is a factor, so x-1 = 0
x - 1 = 0
x = 1.

Given equation :
$4 {x}^{3} + 3 {x}^{2} - 4x + k = 0 \\ put \: x = 1 \\ \\ 4(1 {)}^{3} + 3(1 {)}^{2} - 4(1) + k = 0 \\ 4 + 3 - 4 + k = 0 \\ 3 + k = 0 \\ k = - 3$


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Hope it may help you..

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