Question

find the value of k.

Answer 1

Heya.....^_^

Here's ur ans. ⬇

✨________________________________________________✨

On cross multiplication

↪ 12 × 3 = k ( k -9)

36 = k^2 - 9k

k^2 - 9k - 36 = 0

k^2 - 12k + 3k - 36 = 0

k( k - 12) + 3 ( k - 12 ) = 0

(k+3) (k-12) = 0

(k+3) = 0

↪ k = -3

(k - 12) = 0

↪k = 12

__________________________

✌Hope it helps

Answer 2

Hey!!!

As promised I am here to help you

_____________

Let's solve

=> On Cross Multiplying the two fractions

$= > \frac{3}{k} = \frac{(k - 9)}{12}$

=> 36 = k² - 9k

=> k² - 9k - 36 = 0

By middle term splitting method

=> 36 = 12 x 3

=> k² - 12x + 3x - 36 = 0

=> k(k - 12) + 3(x - 12) = 0

=> (k - 12)(k + 3) = 0

=> k = 12 or k = -3

_____________

Hope this helps ✌️

Good Night :-)