Question

Find the Value of K

(-5/11)K+2 ÷ (-5/11)-4K+5 = (-5/11)2K​

Answer 1

Answer:

k = 1

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Step-by-step explanation:

${ \frac{ - 5}{11} }^{k + 2} \div { \frac{ - 5}{11} }^{( - 4k + 5)} = { \frac{ - 5}{11} }^{2k} \\ \frac{ { \frac{ - 5}{11} }^{k + 2} }{ { \frac{ - 5}{11} }^{ - 4k + 5} } = { \frac{ - 5}{11} }^{2k} \\ { \frac{ - 5}{11} }^{(k + 2) - ( - 4k + 5)} = { \frac{ - 5}{11} }^{2k} \\ { \frac{ - 5}{11} }^{5k - 3} = { \frac{ - 5}{11} }^{2k}$

Now we know that:

${a}^{m} = {a}^{n}$

then, m = n

Therefore,

$5k - 3 = 2k \\ 5k - 2k = 3 \\ 3k = 3 \\ k = 1$

Answer 2

Question

Find the Value of K   ------   (-5/11)K+2 ÷ (-5/11)-4K+5 = (-5/11)2K

​Answer:

K=1

Step-by-step explanation: